sweetmintmojo ([info]sweetmintmojo) wrote,
@ 2008-04-30 02:12:00
Previous Entry  Add to memories!  Tell a Friend  Next Entry
Current mood: geeky
Current music:the kooks, so I'm homesick, alright?
Entry tags:marxism, maths

Stereotypical MIT Discussion
At 2:11 in the morning, after crawling in from the cold after a fire alarm evacuation, we somehow ended up modeling Marxism as a damped harmonic oscillator that goes through one period of oscillation before going to equilibrium (Communist ideology on y-axis, time on x-axis). Communism in practice, though, only goes oscillates through pi/2 before coming to equilibrium.

Think we may have to add further exponential decay for very large t, but not sure best way to do this. Perhaps something involving unit step function.

I should really go to bed.


(Read 2 comments) - (Post a new comment)

Simple Harmonic Politics
[info]shirley_1989
2008-11-01 06:00 pm UTC (link)
From the above statement, I am assuming that equilibrium is in fact that the magnitude of communism has come to rest and is no longer oscillating. However, using your theory that Communism only oscillates through pi/2, one could say communism follows a parabolic motion. Or you could use the following transformation:
- Communism = Capitalism.

Though if the graph starts at 0 like a sin graph, then arguably the capitalists have it slightly better since they have an uninterrupted period (or that should be half period) of negative d(communism)/dt.

I really should be doing my physics assignment, it's just that this is what I'm covering at the minute.

(Reply to this)

(Read 2 comments) - (Post a new comment)

Create an Account
Forgot your login or password?
Login w/ OpenID
English • Español • Deutsch • Русский…